Two gases A and B having the same volume diffuse through a porous partition in 20 and 10 second respectively. The molecular mass of A is 49u. Molecular mass of B will be

  • Option 1)

    50.00u

  • Option 2)

    12.25u

  • Option 3)

    6.50u

  • Option 4)

    25.00u

 

Answers (1)
P perimeter

 

Graham’s law of diffusion -

\dpi{100} r_{1}/r_{2}=\sqrt{M_{1}/M_{2}}  where r is rate of diffusion of gas , M is molar mass.

-

 

 As we know \frac{r_{A}}{r_{B}} =\frac{v/t_{A}}{V/t_{B}} =\sqrt{\frac{mB}{MA}}

=>\frac{10}{20}=\sqrt{\frac{M_{B}}{49}}

=>(\frac{1}{2})^{2}=\frac{MB}{49}

=>M_{B} =\frac{49}{4} =12.254


Option 1)

50.00u

This is incorrect answer

Option 2)

12.25u

This is correct answer

Option 3)

6.50u

This is incorrect answer

Option 4)

25.00u

This is incorrect answer

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