1 more ques. I wanna ask.... As shown in the figure,an ideal gas is taken through the cycle ABCA. If net heat supplied in the cycle is 5J.The work done by the gas in the process A->B is

Answers (1)

 Process B to C at constant volume W_{BC}= 0

Process C to A at constant pressure W_{CA}= P\Delta V= 2(6-4)=4J

As volume of gas is increasing work done is positive.

As the entire process is cyclic.

so \Delta U=0

\Delta Q=\Delta W+\Delta U\Rightarrow W_{AB}+W_{BC}+W_{CA}

5=W_{AB}+0+4

W_{AB}=1J

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