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  • At a point  , there is an electic field of <img alt="500V/m" src="https://entrancecorner.oncodecogs.com/gif.lat

At a point  A, there is an electic field of 500V/m   and potential difference of 3000 V. The distance between the point charge and A is- 

Option: 1

6M


Option: 2

36M


Option: 3

12M


Option: 4

144M


Answers (1)

best_answer

Electric field E=\frac{kq}{r^{2}}
Electric potential V=\frac{kq}{r}
Now,  \frac{V}{E}=\frac{kq}{r}\times\frac{r^{2}}{kq}=r
           r=\frac{V}{E}=\frac{3000}{500}=6\ m

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seema garhwal

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