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Barium ions, CN- and CO2+ form an ionic complex. If this complex is 75% ionised in aqueous solution with Vant Hoff factor (i) equal to four and paramagnetic moment is found to be 1.73 BM(due to spin only) then the hybridisation state of CO(II) in the complex will be :

Option: 1

sp3d
 


Option: 2

d2sp3


Option: 3

sp3d2

 


Option: 4

dsp3


Answers (1)

 

Inner sphere complex -

Complexes in which (n-1)d orbitals are used in hyberdisation.

- wherein

For example: d^{2} sp^{3} hybrid \left [ Fe\left ( CN \right )_{6} \right ]

 

 

 

Strong Field Ligand -

These are the ligands which pair the electron in inner d-orbital and makes required d-orbitals empty/available. 

- wherein

For example: CO, CN etc

 

 

 

 

 

 

Ba_{(x-2)}[Co(CN)_{x}]_{2}\rightarrow (x-2)Ba^{2+}+2[Co(CN)_{x}]^{(x-2)}

1-\alpha                                (x-2)\alpha                                      2\alpha

i=1-\alpha +x\alpha -2\alpha +2\alpha

(x-1)\alpha =3\; x-1=\frac{3}{\alpha }

\alpha =0.75;     x=5

\therefore formula of complex is Ba_{3}[Co(CN)_{5}]_{2} and hybridisation is dsp3 as it is a inner orbital complex with strong field ligand.

 

Posted by

Ramraj Saini

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