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  • Calculate the induced dipole moment per unit volume of helium gas placed in an electric field of <img alt="\mathrm{6 \times 10^5 \mathrm{v} / \mathrm{m} }" src="https://entrancecorner.oncodecogs.co

Calculate the induced dipole moment per unit volume of helium gas placed in an electric field of \mathrm{6 \times 10^5 \mathrm{v} / \mathrm{m} }. The molecular polarizability is \mathrm{2.33 \times 10^{-41} farad -m^2 } and the density of helium is  \mathrm{20.6 \times 10^{25} molecule / \mathrm{m}^3. }

Option: 1

4.76 \times 10^{-9} \mathrm{c} / \mathrm{m}^2


Option: 2

6.44 \times 10^{-9} \mathrm{c} / \mathrm{m}^2


Option: 3

5.64 \times 10^{-9} \mathrm{c} / \mathrm{m}^2


Option: 4

2.88 \times 10^{-9} \mathrm{c} / \mathrm{m}^2


Answers (1)

best_answer

If p is the average dipole moment indeed in each molecule then induced dipole moment per unit volume will be -
p= \mathrm{n \rho }
where n is the number of helium molecules per unit volume and \mathrm{\rho=\alpha \cdot E }
thus,
\mathrm{\begin{aligned} & P=n \alpha E \\ & P=20.6 \times 10^{25} \times 2.33 \times 10^{-41} \times 6 \times 10^5 \\ & P=2.88 \times 10^{-9} \mathrm{c} / \mathrm{m}^2 \text { Ans } \end{aligned} }

Posted by

Ritika Jonwal

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