Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa

Calculate the pressure exerted by 8.5gof ammonia (NH3) contained in a 0.5L vessel at 300K. For ammonia, a=4.0 atm L2mol-2, b=0.036 L mol-1

Answers (1)

\\\text{Number of moles of ammonia }\\\\ n=\frac{8.5}{17}=0.5 \mathrm{mol}$ \\\\ According to van der Waals equation\\ \\ $\left(P+\frac{a n^{2}}{V^{2}}\right)(V-n b)=n R T$\\\\ $P=\frac{n R T}{(V-n b)}-\frac{a n^{2}}{V^{2}}=\frac{0.5 \times 0.082 \times 300}{(0.5-0.5 \times 0.036)}-\frac{4(0.5)^{2}}{(0.5)^{2}}$ $=21.51 a t m$

Posted by

lovekush

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Karnataka AYUSH UG 2025: Round 3 stray vacancy registration begins; option entry ends in two days
anam-khan

Maharashtra NEET UG 2025: Just 114 marks enough for private MBBS seat; govt colleges close at 500
anam-khan

UP NEET AYUSH 2025: Stray vacancy round 3 schedule out; registration ends in two days

Latest Question