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  • Can someone explain Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 x 109 constant, Z = 2 and h(Planck's Constant) = 6.6 x 10- 34 J s]

Consider 3rd orbit of He+ (Helium), using non-relativistic approach, the speed of electron in this orbit will be [given K = 9 x 109 constant, Z = 2 and h(Planck's Constant) = 6.6 x 10- 34 J s]

  • Option 1)

    0.73 x 106 m/s

  • Option 2)

    3.0 x l08 m/s

  • Option 3)

    2.92 x l06 m/s

  • Option 4)

    1.46 x l06 m/s

 

Answers (1)

best_answer

Speed of electron in an orbit is 

v(\frac{c}{137}).\frac{z}{n}=\frac{10^{8}}{137}\times2

v=1.46 \times 10^{6} m/s


Option 1)

0.73 x 106 m/s

this option is incorrect.

Option 2)

3.0 x l08 m/s

this option is incorrect.

Option 3)

2.92 x l06 m/s

this option is incorrect.

Option 4)

1.46 x l06 m/s

this option is correct.

Posted by

Aadil

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