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# Medical

A gene locus has two alleles A,a. If the frequency of dominant allele A is 0.4 ,then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population ?

 

  • Option 1)

    0.36(AA);0.48(Aa);0.16(aa)

  • Option 2)

    0.16(AA);0.24(Aa);0.36(aa)

  • Option 3)

    0.16(AA);0.48(Aa);0.36(aa)

  • Option 4)

    0.16(AA);0.36(Aa);0.48(aa)

Answers (1)
S solutionqc

 

The Hardy-Weinberg formulas -

This formula allows detecting  frequencies that change from generation thus allowing a simplified method of determining that evolution is occurring.

- wherein

In a population at equilibrium for a locus of two alleles D and d having frequencies p and q respectively, the genotype frequencies are: 

DD=p2,

Dd= 2 pq,

dd= q2 

and p+q =1

p2+2 pq +q2 = 1

 

 

Given : \rho =0.4

   So,  q=0.6

Therefore,

  • frequency of homozygous dominant (AA)=p^{2}=0.16
  • frequency of heterozygous(Aa)=2pq=0.48
  • frequency of homozygous recessive(aa)=q^{2}=0.36

Option 1)

0.36(AA);0.48(Aa);0.16(aa)

Option 2)

0.16(AA);0.24(Aa);0.36(aa)

Option 3)

0.16(AA);0.48(Aa);0.36(aa)

Option 4)

0.16(AA);0.36(Aa);0.48(aa)

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