Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Can someone explain - Genetics and Evolution - NEET

A gene locus has two alleles A,a. If the frequency of dominant allele A is 0.4 ,then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population ?

 

  • Option 1)

    0.36(AA);0.48(Aa);0.16(aa)

  • Option 2)

    0.16(AA);0.24(Aa);0.36(aa)

  • Option 3)

    0.16(AA);0.48(Aa);0.36(aa)

  • Option 4)

    0.16(AA);0.36(Aa);0.48(aa)

Answers (1)

best_answer

 

The Hardy-Weinberg formulas -

This formula allows detecting  frequencies that change from generation thus allowing a simplified method of determining that evolution is occurring.

- wherein

In a population at equilibrium for a locus of two alleles D and d having frequencies p and q respectively, the genotype frequencies are: 

DD=p2,

Dd= 2 pq,

dd= q2 

and p+q =1

p2+2 pq +q2 = 1

 

 

Given : \rho =0.4

   So,  q=0.6

Therefore,

  • frequency of homozygous dominant (AA)=p^{2}=0.16
  • frequency of heterozygous(Aa)=2pq=0.48
  • frequency of homozygous recessive(aa)=q^{2}=0.36

Option 1)

0.36(AA);0.48(Aa);0.16(aa)

Option 2)

0.16(AA);0.24(Aa);0.36(aa)

Option 3)

0.16(AA);0.48(Aa);0.36(aa)

Option 4)

0.16(AA);0.36(Aa);0.48(aa)

Posted by

solutionqc

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NTA declares NEET UG result 2025 withheld after MP HC orders over power outage during exam
anam-khan

MCC NEET UG counselling 2025 registration from July 21 for MBBS, BDS, AYUSH admissions
anam-khan

From 589 to 41: NEET candidate misses cut-off over silly error, HC orders re-checking of OMR sheet

Latest Question