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A circular coil ABCD carrying a current i is placed in a uniform magnetic field. If the magnetic force on the segment AB is \vec{F}, the force on the remaining segment BCDA is

  • Option 1)

    \vec{F}

  • Option 2)

    -\vec{F}

  • Option 3)

    3\vec{F}

  • Option 4)

    -3\vec{F}

 

Answers (1)

best_answer

 

Torque -

underset{T}{
ightarrow}=underset{M}{
ightarrow}	imes underset{B}{
ightarrow}=M=NiA

T=MBsin 	heta =NBiAsin 	heta

 

- wherein

M - magnetic moment 

 

 net force on the loop  =0

\vec{F}=0

\vec{F}_{AB}+\vec{F}_{BCDA}=0

\vec{F}_{BCDA}=-\vec{F}_{AB}=-\vec{F}


Option 1)

\vec{F}

Incorrect Option

Option 2)

-\vec{F}

Incorrect Option

Option 3)

3\vec{F}

Incorrect Option

Option 4)

-3\vec{F}

Correct Option

Posted by

Aadil

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