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  • Can someone explain One end of string of length 1is connected to a particle of mass 'm' and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed v, the net force on the particle (d

One end of string of length 1  is connected to a particle of mass 'm' and the other end is connected to a small peg on a smooth horizontal table. If the particle moves in circle with speed v, the net force on the particle (directed towards centre) will be (T represents the tension in the string)

  • Option 1)

    T+\frac{mv^{2}}{1}

  • Option 2)

    T-\frac{mv^{2}}{1}

  • Option 3)

    zero

  • Option 4)

    T

 

Answers (1)

best_answer

As we learnt in 

Centripetal Force -

F=4mpi^{2}n^{2}r

F=frac {4mpi^{2}n^{2}r} {T^{2}}

F = Centripetal force

omega= Angular velocity

n = frequency

- wherein

Force acts on the body along the radius and towards centre.

 

 T=F-\frac{mv^{2}}{l}

F is net force acting on particle.


Option 1)

T+\frac{mv^{2}}{1}

Correct

Option 2)

T-\frac{mv^{2}}{1}

Incorrect

Option 3)

zero

Incorrect

Option 4)

T

Incorrect

Posted by

Plabita

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