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  • Can someone explain The second overtone of an organ pipe has the same frequency as the first overtone of a closed pipe L metre long. The length of the open pipe will be

The second overtone of an organ pipe has the same frequency as the first overtone of a closed pipe L metre long. The length of the open pipe will be

  • Option 1)

    L

  • Option 2)

    2L

  • Option 3)

    \frac{L} {2}

  • Option 4)

    4L

 

Answers (2)

best_answer

As we discussed in

The frequency in open organ pipe -

u = ncdot frac{V}{2l}

n= 1,2,3.......

- wherein

V= velocity of sound wave

l= length of pipe

n= number of overtones

 

 Second overtone of an open organ pipe

3rd harmonic = 3 v_{0}^{'} =3\times \frac{v}{2L}

First overtone of a closed organ pipe

3rd harmonic =3 v_{0} =3\times \frac{v}{4L}

According to question

\because 3 v_{0}^{'} =3v_{0}=3\times \frac{v}{2L^{'}}=3\times \frac{v}{2L}

\therefore L^{'}=2L

 


Option 1)

L

Incorrect option

Option 2)

2L

Correct option

Option 3)

\frac{L} {2}

Incorrect option

Option 4)

4L

Incorrect option

Posted by

divya.saini

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2L

 

Posted by

Anshul Kanojiya

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