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A long solenoid has 1000 turns. When a current of 4A flows through it, the magnetic flux linked with each turn of the solenoid is 4 x 10-3 Wb. The self-inductance of the solenoid is:

  • Option 1)

    4 H

  • Option 2)

    3 H

  • Option 3)

    2 H

  • Option 4)

    1 H

 

Answers (1)

best_answer

As discussed in

Co efficient of self induction -

phi , alpha , IRightarrow Nphi , alpha: I

Nphi ,=L, I

L=frac{Nphi }{I},
 

- wherein

Nphi = Number of flux linkage with coil.

 

 

N=1000, \:\:\:\:\:I=4A, \:\:\:\:\:\phi_{o}=4 \times 10^{-3}wb

Total flux linked with the solenoid, \phi =N \phi _o\phi=1000 \times 4 \times 10^{-3}wb=4wb

\phi=LI\:\:\:\:\:\Rightarrow L=\frac{\phi}{I}=\frac{4wb}{4A}=1H


Option 1)

4 H

This option is incorrect.

Option 2)

3 H

This option is incorrect.

Option 3)

2 H

This option is incorrect.

Option 4)

1 H

This option is correct.

Posted by

Aadil

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