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  • Can someone help me with this, - Atoms And Nuclei - NEET

Radioactive material 'A' has decay constant '8\lambda' and material 'B' has decay constant '\lambda'. Initially they have same number of nuclei. After what time, the ratio of number of nuclei of material 'B' to that 'A' will be \frac{1} {e} ?

  • Option 1)

    \frac{1} {\lambda }

  • Option 2)

    \frac{1} {{7\lambda }}

  • Option 3)

    \frac{1} {{8\lambda }}

  • Option 4)

    \frac{1} {{9\lambda }}

 

Answers (1)

best_answer

 

Number of nuclei after disintegration -

N=N_{0}e^{-lambda t} or A=A_{0}e^{-lambda t}

- wherein

Number of nucleor activity at a time is exponentional function

 

 At any time t, number of nuclei

 

N= No.e-\lambda t 

For A, NA = No e-8\lambda t 

For B, NB = No e-\lambda t

\frac{N_{B}}{N_{A}}=\frac{1}{e}=e^{-7\lambda t}

=7\lambda t= 1 \ or \ t=\frac{1}{7\lambda }


Option 1)

\frac{1} {\lambda }

this is the incorrect option

Option 2)

\frac{1} {{7\lambda }}

this is the correct option

Option 3)

\frac{1} {{8\lambda }}

this is the incorrect option

Option 4)

\frac{1} {{9\lambda }}

this is the incorrect option

Posted by

Aadil

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