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Which of the following complex compounds will exhibit highest paramagnetic behaviour?
(At No.: Ti=22, Cr=24, Co=27, Zn=30)

  • Option 1)

    \left [ Ti(NH_{3})_{6} \right ]^{3+}

  • Option 2)

    \left [ Cr(NH_{3})_{6} \right ]^{3+}

  • Option 3)

    \left [ Co(NH_{3})_{6} \right ]^{3+}

  • Option 4)

    \left [ Zn(NH_{3})_{6} \right ]^{2+}

 

Answers (1)

As we learnt in

Hybridisation -

sp3d2 - square bipyramidal or octahedral 

d2sp3 - octahedral 

sp3 - tetradedral 

dsp2 - square planar

- wherein

sp3d2 - outer complex

d2sp3 - inner complex

sp3 - [Ni(Cl)_{4}]^{2-}

dsp2 - [Pt(CN)_{4}]^{2-}

 

Electronic configuration of Cr3+ in [Cr(NH3)6]3+:

 

Electronic configuration of Ti3+ in [Ti(NH3)6]3+

Electronic configuration of CO3+ in [CO(NH3)6]3+

Electronic configuration of Zn2+ in [Zn(NH3)6]2+

Since Cr3+ has maximum number of unpaired electron it will exhibit highest paramagnetic nature.

 


Option 1)

\left [ Ti(NH_{3})_{6} \right ]^{3+}

Incorrect

Option 2)

\left [ Cr(NH_{3})_{6} \right ]^{3+}

Correct

Option 3)

\left [ Co(NH_{3})_{6} \right ]^{3+}

Incorrect

Option 4)

\left [ Zn(NH_{3})_{6} \right ]^{2+}

Incorrect

Posted by

Vakul

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