Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Confused! kindly explain, A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will

A charge Q is enclosed by a Gaussian spherical surface of radius R. If the radius is doubled, then the outward electric flux will

  • Option 1)

    increase four times

  • Option 2)

    be reduced to half

  • Option 3)

    remain the same

  • Option 4)

    be doubled

 

Answers (1)


@9715

Gauss's Law -

Total flux linked with a closed surface called Gaussian surface.

Formula:

\phi = \oint \vec{E}\cdot d\vec{s}=\frac{Q_{enc}}{\epsilon _{0}}

 

- wherein

No need to be a real physical surface.

Qenc - charge enclosed by closed surface.

 

    electric flux through a surface = \frac{q_{in}}{\epsilon _{0}}

since q_{in} is constant, flux will remain same.

 


Option 1)

increase four times

Incorrect

Option 2)

be reduced to half

Incorrect

Option 3)

remain the same

Correct

Option 4)

be doubled

Incorrect

Posted by

Vakul

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2024 exam city slip out at neet.ntaonline.in; over 25 lakh candidates to appear
anam-khan

NEET UG city intimation slip likely today at exams.nta.ac.in/NEET; barred item at exam centre
anam-khan

NEET UG 2024 exam city slip soon; admit card updates

Latest Question