A force F  = 20 + 10 y acts on a particle in y - direction  where F  is in newton and y in meter  Work done by this force to move the particle from y = 0 to y = 1 is : 

  • Option 1)

    30 J 

  • Option 2)

    5 J 

  • Option 3)

    25 J 

  • Option 4)

    20 J 

Answers (1)

F = 20+ 10 y \\\\ W = F\cdot ds \\\\ here W = F\cdot dy = ( 20 + 10 y ) dy \\\\ W = [ 20 y ]^1 _0 + \left [ \frac{10 y^2}{2} \right ]^1_0 \\\\ W = 20+5 = 25 J


Option 1)

30 J 

Option 2)

5 J 

Option 3)

25 J 

Option 4)

20 J 

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