For CE transistor amplifier, the audio signal voltage across the collector resistance of 2\text{k}\Omega is 4 V. If the current amplification factor of the transistor is 100 and the base resistance is 1\text{k}\Omega, then the input signal voltage is

  • Option 1)

    10 mV

  • Option 2)

    20 mV

  • Option 3)

    30 mV

  • Option 4)

    15 mV

 

Answers (1)

As we learnt in 

Transistor -

Three layered semiconducting device .

NPN or PNP

- wherein

1.    Emitter is heavily doped

2.    collector is moderately doped .

3.    Base is lightly doped & very thin

 

 V_{0}=4V

R_{L}=2K\Omega

B=100

R_{in}=1K\Omega          

\frac{V_{0}}{V_{i}}=\beta.\frac{R_{L}}{R_{in}}

\Rightarrow \frac{4}{V_{in}}=100\times \frac{2K\Omega }{1K\Omega }=200

\Rightarrow V_{in}=\frac{1}{50}V=20mV     


Option 1)

10 mV

This solution is incorrect 

Option 2)

20 mV

This solution is correct 

Option 3)

30 mV

This solution is incorrect 

Option 4)

15 mV

This solution is incorrect 

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