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A square loop, carrying a steady current I, is placed in a horizontal plane near a long straight conductor carrying a steady current I_{1} at a distance d from the conductor as shown in the figure. The loop will experience

  • Option 1)

    A net repulsive force away from the conductor

  • Option 2)

    A net torque acting upward perpendicular to the horizontal plane

  • Option 3)

    A net torque acting downward normal to the horizontal plane

  • Option 4)

    A net attractive force towards the conductor

 

Answers (1)

 

Force between two parallel current carrying conductors -

F=frac{mu }{4pi } frac{2I_{1 I_{2}}}{a} l

frac{F}{l}=frac{mu o}{4pi } frac{2I_{1 I_{2}}}{a}

- wherein

I1 and I2 current carrying two parallel wires 

a-seperation between two wires 

 

 Since magnetic moment and field both are parallel hence torque=0

But there will be an attractive force becuase of parallel current between wire and loop will attract more than repulsive force between anti parallel currents 


Option 1)

A net repulsive force away from the conductor

This solution is incorrect 

Option 2)

A net torque acting upward perpendicular to the horizontal plane

This solution is incorrect 

Option 3)

A net torque acting downward normal to the horizontal plane

This solution is incorrect 

Option 4)

A net attractive force towards the conductor

This solution is correct 

Posted by

Vakul

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