Out of the following which one is not a possible energy for a photon to be emitted by hydrogen atom according to Bohr,s atomic model?

  • Option 1)

    1.9 eV

  • Option 2)

    11.1\:eV

  • Option 3)

    13.6\:eV

  • Option 4)

    0.65\:eV

 

Answers (1)

As learnt

Energy emitted due to transition of electron -

Delta E= Rhcz^{2}left ( frac{1}{n_{f}, ^{2}}-frac{1}{n_{i}, ^{2}} 
ight )

frac{1}{lambda }= Rz^{2}left ( frac{-1}{n_{i}, ^{2}}+frac{1}{n_{f}, ^{2}} 
ight )

- wherein

R= R hydberg: constant

n_{i}= initial state \n_{f}= final : state

 

E_{1}=-13.6 eV                                    E_{3}-E_{2}=-1.5-(-3.4)=1.9eV

E_{2}=\frac{-13.6}{4}=-3.4                         E_{4}-E_{3}=-0.85-(-1.51)=0.65eV

E_{3}=-1.51eV

E_{4}=\frac{-13.6}{16}=-0.85              

Energy emitted by hydrogen atom are 10.2 ev, 12.09, 12.75, -----------------------------------------

So, 11.1 ev is not possible.


Option 1)

1.9 eV

Incorrect

Option 2)

11.1\:eV

Correct

Option 3)

13.6\:eV

Incorrect

Option 4)

0.65\:eV

Incorrect

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