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Consider an ionic solid with the formula \text{AB}_2\text{X}_4, where A, B, and X are elements. If the coordination number of A ions is 6 and the coordination number of X ions is 4, what is the coordination number of B ions?

Option: 1

2


Option: 2

4


Option: 3

6


Option: 4

8


Answers (1)

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In an ionic solid, the coordination number refers to the number of ions that surround a particular ion. Given that the coordination number of A ions is 6, it means that each A ion is surrounded by 6 X ions. Similarly, the coordination number of X ions is 4, indicating that each X ion is surrounded by 4 A ions. Since the formula of the ionic solid is\text{AB}_2\text{X}_4, it implies that there are 2 B ions for every A ion. Thus, the coordination number of B ions would be half of the coordination number of A ions, i.e., 3. Hence, the correct answer is option (1) 2.

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