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  • Consider the reaction given below <img alt="\mathrm{CH_3-CH=CH_2+HX\rightarrow A\: \: (major \: product)}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BCH_3-CH%3DCH_2&

Consider the reaction given below

\mathrm{CH_3-CH=CH_2+HX\rightarrow A\: \: (major \: product)}

The major product A is 

Option: 1

CH_3CH_2CH_2X


Option: 2

CH_3CHXCH_3


Option: 3

both (i) and (ii)


Option: 4

None of these


Answers (1)

best_answer

As we learnt,

The asymmetrical alkenes follow Markovnikov's rule during addition forming secondary or tertiary alkyl halides as the corresponding carbocations are relatively stable.

In case of propene, a secondary halide will be obtained as the major product.

\mathrm{CH_3-CH= CH_2 +HX \rightarrow CH_3-CH(X)-CH_3}

Hence, the correct answer is Option (2)

Posted by

Riya

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