# Convex lens is put 10 cm from a light source and it makes a sharp image on a screen, kept 10 cm from the lens. Now a glass block (refractive index1.5) of 1.5 cm thickness is placed in contact with the light source. To get the sharp image again, the screen is shifted by a distance d. Then d is:-

Refraction through parallel slab -

- wherein

shifting of object from slab

thickness of slab

Refractive Index of slab.

F =  = 5 cm

Due to glass plate shift

s = t

= 1.5

= 0.5

New u =9.5 cm

Using lens formula

v = 10.55 cm

Shift  is 0.55 cm away from the lens.

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