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  • Figure shows two bulbs  and <img alt="\mathrm{B}_2," src="https://entrancecorner.oncodecogs.c

Figure shows two bulbs \mathrm{B}_1 and \mathrm{B}_2, resistor \mathrm{R} and an inductor \mathrm{L}. When the switch \mathrm{S} is turned off,
   

Option: 1

both\mathrm{ \mathrm{B}_1 \, and\, \mathrm{B}_2} die out promptly


Option: 2

both \mathrm{ \mathrm{B}_1 \, and\, \mathrm{B}_2} die out with some delay


Option: 3

\mathrm{B}_1 dies out promptly but \mathrm{B}_2 with some delay


Option: 4

\mathrm{B}_2 dies out promptly but \mathrm{B}_1 with some delay


Answers (1)

best_answer

Here the bulb \mathrm{B}_1 will die out promptly but \mathrm{B}_2 with some delay. The reason is that the branch of bulb \mathrm{B}_2 contains inductance. Due to the effect in inductance, the current in this branch continues to flow for sometime even the switch \mathrm{S} is turned off.

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rishi.raj

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