Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • Find out the solubility of   in <img alt="0.1 M NaOH" src="https://entrancecorner.onc

Find out the solubility of Ni(OH)_{2}  in 0.1 M NaOH. Given that the ionic product of Ni(OH)_{2} is 2 \times 10^{-15}

Option: 1

1 \times 10^{8}M
 


Option: 2

2 \times 10^{-13}M


Option: 3

2 \times 10^{-8}M

 


Option: 4

1 \times 10^{-13}M


Answers (1)

best_answer

The reaction occurs as follows:

\mathrm{Ni(OH)_{2}\: \rightleftharpoons \: Ni^{2+}\: +\: 2OH^{-}}

      (s)                     (s)                0.1+2s \sim 0.1

Thus, s(0.1)^{2}=2 \times 10^{-15}

s=2 \times 10^{3}

Therefore, Option(2) is correct.

Posted by

vinayak

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

MCC NEET UG 2024 Counselling: Special round schedule out; choice filling begins from November 20
anam-khan

Rajasthan NEET UG counselling board cancels MBBS admissions of 100 students at PMCH
anam-khan

100 MBBS students’ fate uncertain as HC reverses ruling on extra seats at Rajasthan private medical college

Latest Question