Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • For a projectile, the ratio of maximum height reached to the square of flight time is <img alt="\mathrm{ \left(g=10 \mathrm{~m} / \mathrm{s}^2\right)}" src="https://entrancecorner.oncodecogs.c

For a projectile, the ratio of maximum height reached to the square of flight time is \mathrm{ \left(g=10 \mathrm{~m} / \mathrm{s}^2\right)}
 

Option: 1

5: 4


Option: 2

5: 2


Option: 3

5: 1


Option: 4

10: 1


Answers (1)

best_answer

 Maximum height (H ) 
\mathrm{=\frac{u^2 \sin ^2 \theta}{2 g}} \\
 Flight time (T)
\mathrm{=\frac{2 u \sin \theta}{g}}
Ratio of maximum height reached to the square of flight time - 
\mathrm{\begin{aligned} & \frac{H}{T^2}=\frac{u^2 \sin ^2 \theta}{2 g} \times \frac{g^2}{4 u^2 \sin ^2 \theta} \\ & \frac{H}{T^2}=\frac{g}{8}=\frac{10}{8} \\ & \frac{H}{T^2}=\frac{5}{4} \text { Ans. } \end{aligned}}

Posted by

HARSH KANKARIA

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

MP HC allows NTA to declare NEET UG 2025 results except for 11 centres in Indore
anam-khan

NEET UG 2025: HC grants stay on result after Chennai students point to power cut in exam centre
anam-khan

CENTAC Puducherry to host interactive session for Non-NEET UG courses at 6 pm today

Latest Question