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  •  For a reversible reaction A  B, the equilitrion constant

 For a reversible reaction A \rightleftharpoons B, the equilitrion constant ( k_e ) is given as k_e=(13) /(17 P.) Choose the correct expression for k_q in terms of the rate constants \left(k_1 \& k_{-1}\right) of the forward it reverse reactions.
 

Option: 1

\quad k_{e q}=k_1 / k_{-1}
 


Option: 2

k_{e q}=k_{-1} / k_1
 


Option: 3

\quad k_{e q}=k_1 \times k_{-1}
 


Option: 4

k_q=k_1+k_{-1}
 


Answers (1)

best_answer


The equilibrium constant ( k eq) of the revers isle reaction is the ratio of the rate constant for the forcer reaction \left(k_1\right) of the reverse reaction \left(k_{-1}\right).

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Anam Khan

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