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  • For a second-order reaction, if the concentration of the reactant is tripled, the rate of the reaction becomes:.  Option: 1 Three times o

For a second-order reaction, if the concentration of the reactant is tripled, the rate of the reaction becomes:.
 

Option: 1

Three times of the original rate


 


Option: 2

Nine times of the original rate
 


Option: 3

six times of the original rate
 


Option: 4

Remains same.


Answers (1)

for a second order \mathrm{R \times A}

\mathrm{ R=k(A)^2 }

If \mathrm{ A \longrightarrow 3 A }

\mathrm{ R^{\prime}=K(3 A)^2=9\: \: K(A)=9 R }

\mathrm{ R^{\prime}=9 R }

Hence option 2 is correct.






 

Posted by

Sumit Saini

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