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From Ampere's circuital law for a long straight wire of circular cross section carrying a steady current, the variation of magneic field in the inside and outside region of the wire is :

Option: 1

A linearly increasing function distance upto the boundary of the wire and then linearly decreasing for the outside region


Option: 2

A linearly increasing function distance r upto the boundary of the wire and then decreasing with 1/r for the outside region


Option: 3

A linearly increasing function distance upto the boundary of the wire and then linearly increasing one for the outside region


Option: 4

uniform and remains constant for both the regions.


Answers (1)

best_answer

\mathrm{B_{\text {inside }}=\frac{\mu_{0} i r}{2 \pi R^{2}}}               \mathrm{(r\leq R)}

\mathrm{\text { Boutside }=\frac{\mu_{0} i}{2 \pi r}(r>R)}

Hence the correct option is 2

Posted by

vinayak

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