#### In a population of 1000 individuals 360 belong to genotype AA, 480 to Aa and the remaining 160 to aa. Based on this date, the frequency of allele A in the population is: Option 1) 0.4 Option 2) 0.5 Option 3) 0.6 Option 4) 0.7

The Hardy-Weinberg formulas -

This formula allows detecting  frequencies that change from generation thus allowing a simplified method of determining that evolution is occurring.

- wherein

In a population at equilibrium for a locus of two alleles D and d having frequencies p and q respectively, the genotype frequencies are:

DD=p2,

Dd= 2 pq,

dd= q2

and p+q =1

p2+2 pq +q= 1

According to Hardy - Weinberg principle

In a population at equilibrium for a locus of two alleles D and d having frequencies p and q respectively, the genotype frequencies are:

DD=p2,

Dd= 2 pq,

dd= q2

and p+q =1

p2+2 pq +q2 = 1

so,

p2= 36 out of 100 individual

q2= 16 out of 100

q= 0.161/2= 0.4

Option 1)

0.4

This is incorrect option

Option 2)

0.5

This is incorrect option

Option 3)

0.6

This is correct option

Option 4)

0.7

This is incorrect option