A rigid ball of mass m strikes a rigid, wall at 60^\circ and gets reflected without loss of speed as shown in the figure below. The value of impulse imparted by the wall on the ball will be

  • Option 1)

    mV

  • Option 2)

    2mV

  • Option 3)

    \frac{2}

  • Option 4)

    \frac{3}

 

Answers (1)

As we learnt in 

Law of Conservation of Momentum -

 vec{F}=frac{vec{dp}}{dt}

vec{F}=0            then vec{p}=constant

vec{p}=vec{p}_{1}+vec{p}_{2}+cdots =const

- wherein

ast Independent of frame of reference

 

 

After doing components,

V_{1}= V \frac{\sqrt 3}{2}\hat{i}-V\frac{\sqrt 3}{2}\hat {j}

V_{2}= -V \frac{\sqrt 3}{2}\hat{i}-V\frac{\sqrt 3}{2}\hat {j}

Impulse = mV_{1}-mV_{2}=mV  


Option 1)

mV

Correct

Option 2)

2mV

Incorrect

Option 3)

\frac{2}

Incorrect

Option 4)

\frac{3}

Incorrect

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