Two cars moving in opposite directions approach each other with speed of 22 m/s and 16.5 m/s respectively. The driver of the first car blows a horn having a frequency 400 Hz. The frequency heard by the driver of the second car is [velocity of sound 340 m/s]:

  • Option 1)

    350 Hz

  • Option 2)

    361 Hz

  • Option 3)

    411 Hz

  • Option 4)

    448 Hz

 

Answers (1)
D Divya Saini

As we learnt in

Frequency of sound when source and observer are moving towards each other -

\nu {}'= \nu _{0}.\frac{C+V_{0}}{C-V_{s}}
 

- wherein

C= Speed of sound

V_{0}= Speed of observer

V_{s}= speed of source

\nu _{0 }= Original frequency

\nu {}'= apparent frequency

 

 f_{app}=f_{o}\left[ \frac{v+v_{o}}{v-v_{s}} \right ]=400 \left[ \frac{340+16.5}{340-22} \right ]

\therefore f_{app}=448 Hz


Option 1)

350 Hz

This option is incorrect.

Option 2)

361 Hz

This option is incorrect.

Option 3)

411 Hz

This option is incorrect.

Option 4)

448 Hz

This option is correct.

Exams
Articles
Questions