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  • Help me answer: Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is

Charge  q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction  at the centre of the ring is

  • Option 1)

    \frac{\mu_{o}qf}{2R}

  • Option 2)

    \frac{\mu_{o}q}{2fR}

  • Option 3)

    \frac{\mu_{o}q}{2\pi fR}

  • Option 4)

    \frac{\mu_{o}qf}{2\pi R}

 

Answers (1)

best_answer

 

Magnetic Field due to circular coil at Centre -

B_{Centre}=frac{mu_{0}}{4pi }frac{2pi Ni}{r}=frac{mu_{0} Ni}{2r}

- wherein

X = 0

 

 current in the ring =\frac{q}{T}=qf

\therefore \:B=\frac{\mu _{oi}}{2R}=\frac{\mu _{oqf}}{2R}

 


Option 1)

\frac{\mu_{o}qf}{2R}

This solution is correct 

Option 2)

\frac{\mu_{o}q}{2fR}

This solution is incorrect 

Option 3)

\frac{\mu_{o}q}{2\pi fR}

This solution is incorrect 

Option 4)

\frac{\mu_{o}qf}{2\pi R}

This solution is incorrect 

Posted by

divya.saini

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