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Help me answer: When 1 kg of ice at 0oC melts to water at 0oC, the resulting change in its entropy, taking latent heat of ice to be 80 cal/ oC, is:

When 1 kg of ice at 0o C melts to water at  0o C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/C, is:

  • Option 1)

    273\: cal/ K

  • Option 2)

    8 \times 104\: cal/K

  • Option 3)

    80 \:cal/K

  • Option 4)

    293\:cal/K

 
Answers (1)
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As learnt in

Entropy for solid and liquid -

When heat is given to a substance to change its state at constant temperature.

- wherein

Delta S= frac{mL}{T}

L= Latent , Heat

T in kelvin

 

 \Delta S = \frac{\Delta Q}{T} = \frac{mL}{T}

          = \frac{1000\times 80}{273}\ cal/K

          = 293\ cal/K


Option 1)

273\: cal/ K

This option is incorrect

Option 2)

8 \times 104\: cal/K

This option is incorrect

Option 3)

80 \:cal/K

This option is incorrect

Option 4)

293\:cal/K

This option is correct

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