Q

# Help me answer: When 1 kg of ice at 0oC melts to water at 0oC, the resulting change in its entropy, taking latent heat of ice to be 80 cal/ oC, is:

When 1 kg of ice at 0o C melts to water at  0o C, the resulting change in its entropy, taking latent heat of ice to be 80 cal/C, is:

• Option 1)

$273\: cal/ K$

• Option 2)

$8 \times 104\: cal/K$

• Option 3)

$80 \:cal/K$

• Option 4)

$293\:cal/K$

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As learnt in

Entropy for solid and liquid -

When heat is given to a substance to change its state at constant temperature.

- wherein

$\Delta S= \frac{mL}{T}$

$L= Latent \, Heat$

T in kelvin

$\Delta S = \frac{\Delta Q}{T} = \frac{mL}{T}$

$= \frac{1000\times 80}{273}\ cal/K$

$= 293\ cal/K$

Option 1)

$273\: cal/ K$

This option is incorrect

Option 2)

$8 \times 104\: cal/K$

This option is incorrect

Option 3)

$80 \:cal/K$

This option is incorrect

Option 4)

$293\:cal/K$

This option is correct

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