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Q

Help me please, A set of 'n' equal resistors, of value 'R' each, areconnected in series to a battery of emf 'E' and internal resistance 'R'. The current drawn is I. Now, the 'n' resistors are connected in paral

A set of 'n' equal resistors, of value 'R' each, are
connected in series to a battery of emf 'E' and internal resistance 'R'. The current drawn is I. Now, the 'n' resistors are connected in parallel to the same battery. Then the current drawn from battery becomes 10 I. The value of 'n' is

 

  • Option 1)

    20

  • Option 2)

    11

  • Option 3)

    10

  • Option 4)

    9

 
Answers (1)
211 Views

As we have learned

Main current / current from each cell -

i=frac{nE}{R+nr}

- wherein

n- identical cells which connected in series

 

 

Main current -

i= frac{E}{R+frac{r}{n}}

-

 

 

 

I= \frac{E}{R+nR}    And 10I= \frac{E}{R/n+R}

10I= \frac{nE}{R+nR}= nI

n= 10

 

 

 

 

 

 

 


Option 1)

20

This is incorrect

Option 2)

11

This is incorrect

Option 3)

10

This is correct

Option 4)

9

This is incorrect

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