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# Medical

The mass of a _{3}^{7}\textrm{Li} nucleus is 0.042 u less than the sum of the masses of all its nucleons. the binding energy per nucleon of _{3}^{7}\textrm{Li} nucleus is nearly

  • Option 1)

    46MeV

  • Option 2)

    5.6MeV

  • Option 3)

    3.9MeV

  • Option 4)

    23 MeV

 

Answers (1)
D divya.saini

As we learnt in 

energy mass equivalence -

Delta E=Delta m.c^{2}       

- wherein

Delta m = mass defect

Delta E = energy released

 

 Binding\ Energy = (\Delta m) c^{2} \\ \\ = (0.0424) \: 931 MeV \\ \\ = 38.102 MeV \\ \\ \therefore Binding \: energy \: per \ nucleon = \frac{38.102}{7} \: = 5.5 MeV


Option 1)

46MeV

Incorrect

Option 2)

5.6MeV

Correct

Option 3)

3.9MeV

Incorrect

Option 4)

23 MeV

Incorrect

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