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A npn transistor is connected in common emitter configuration in a given amplifier. A load resistance of 800 \Omega is connected in the collector circuit and the voltage drop across it is 0.8 V. If the current amplification factor is 0.96 and the input resistance of the circuit is 192\Omega, the voltage gain and the power gain of the amplifier will respectively be:

  • Option 1)

    4, 3.84

  • Option 2)

    3.69, 3.84

  • Option 3)

    4, 4

  • Option 4)

    4, 3.69

 

Answers (1)

best_answer

As we learnt in

Transistor -

Three layered semiconducting device .

NPN or PNP

- wherein

1.    Emitter is heavily doped

2.    collector is moderately doped .

3.    Base is lightly doped & very thin

 

 R_{L}=800 \Omega

V_{L}=0.8 V

Current amplification = 0.96

R_{i}=192\Omega

Voltage gain  =\frac{V_{0}}{V_{i}}=\beta.\frac{R_{L}}{R_{i}}

    =0.96 \times \left(\frac{800}{192} \right )=4

Power gain  =\beta^{2}\left(\frac{R_{L}}{R_{i}} \right )

       =0.96\times 0.96 \times\frac{800}{192}

        =0.96 \times \frac{96 \times 8}{192}=3.84

 


Option 1)

4, 3.84

Correct

Option 2)

3.69, 3.84

Incorrect

Option 3)

4, 4

Incorrect

Option 4)

4, 3.69

Incorrect

Posted by

prateek

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