In acidic medium, H2O2 changes to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO5 is:
+5
+3
+6
-10
As we learnt in
Rules for Oxidation Number -
The oxidation number of oxygen in most compounds is -2. There are two exceptions.
In peroxide (H2O2; Na2O2), the oxidation number is -1.
- wherein
In superoxide e.g. KO2 its oxidation number is -1/2.
CrO5 has butterfly structure having two peroxo bonds.
peroxo oxygen has - 1 oxidation state. Let oxidation state of Cr be x.
CrO5 : x + 4( - 1) + 1 (-2) = 0
Correct option is 3.
Option 1)
+5
Incorrect
Option 2)
+3
Incorrect
Option 3)
+6
Correct
Option 4)
-10
Incorrect