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Two identical piano wires kept under the same tension T have a fundamental frequency of 600 Hz. The fractional increase in the tension of one of the wires which will lead to the occurrence of 6 beats/s when both the wires oscillate together would be

  • Option 1)

    0.02

  • Option 2)

    0.03

  • Option 3)

    0.04

  • Option 4)

    0.01

 

Answers (1)

best_answer

As discussed

Fundamental frequency with end correction -


u _{0}= frac{V}{4left ( l+e 
ight )}     (one end open)


u _{0}= frac{V}{2left ( l+2e 
ight )}    (Both end open)

e = end correction

-

 

 v=\frac{1}{2L}\sqrt\frac{T}{\mu}

 

\therefore \frac{\Delta V}{V}=\frac{1}{2}\frac{\Delta T}{T}

\frac{\Delta T}{T} = 2\: \frac{\Delta V}{V}\:=2\times\frac{6}{600}=0.02


Option 1)

0.02

This is correct option

Option 2)

0.03

This is incorrect option

Option 3)

0.04

This is incorrect option

Option 4)

0.01

This is incorrect option

Posted by

prateek

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