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Help me solve this A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s2 at a distance of 5 m from the mean position.

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s2 at a distance of 5 m from the mean position. The time period of oscillation is

  • Option 1)

    2 s

  • Option 2)

    \pi s

  • Option 3)

    2\pi s

  • Option 4)

    1 s

 
Answers (1)
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a=w^{2}x\Rightarrow 20w^{2}\times 5\Rightarrow w=2 rad/sec

T = \frac{2\pi }{w} sec = \pi second

 


Option 1)

2 s

This is incorrect

Option 2)

\pi s

This is correct

Option 3)

2\pi s

This is incorrect

Option 4)

1 s

This is incorrect

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