The input signal given to a CE amplifier having a  voltage gain of 150 is \text{V}_i = \left( {15\text{t} + \frac{{2\pi }} {3}} \right). The corresponding output signal will be :

  • Option 1)

    75\cos \left( {15\text{t} + \frac{{2\pi }} {3}} \right)

  • Option 2)

    2\cos \left( {15\,\text{t} + \frac{{2\pi }} {3}} \right)

  • Option 3)

    300\cos \left( {15\,\text{t} + \frac{{4\pi }} {3}} \right)

  • Option 4)

    300\cos \left( {15\,\text{t} + \frac{\pi } {3}} \right)

 

Answers (1)
P Plabita

As we learnt in

Amplifier -

Transistor is used as an amplifier

- wherein

in such circuit output is amplified as compared to input .

 

Input signal of a CE amplifier, V_{i} = 2\cos \left ( 15\:t+\frac{\pi }{3} \right )

Voltage gain = 150

As CE amplifier give phase difference of \pi between input and output signals,

so A_{v} = \frac{V_{0}}{V_{i}} \Rightarrow V_{0} = A_{v}\cdot V_{i}

V_{0} = 150 \times 2\cos \left ( 15\:t+\frac{\pi }{3} + \pi \right )

V_{0} = 300\cos \left ( 15\:t+\frac{4\pi }{3} \right )


Option 1)

75\cos \left( {15\text{t} + \frac{{2\pi }} {3}} \right)

This option is incorrect

Option 2)

2\cos \left( {15\,\text{t} + \frac{{2\pi }} {3}} \right)

This option is incorrect

Option 3)

300\cos \left( {15\,\text{t} + \frac{{4\pi }} {3}} \right)

This option is correct

Option 4)

300\cos \left( {15\,\text{t} + \frac{\pi } {3}} \right)

This option is incorrect

Exams
Articles
Questions