Which is the correct thermal stability order for H_2E\;(E = O, S, Se, Te \;\textup{and}\;Po)?

  • Option 1)

    H_2S < H_2 O < H_2Se < H_2 Te < H_2Po

  • Option 2)

    H_2O < H_2 S < H_2Se < H_2 Te < H_2Po

  • Option 3)

    H_2Po < H_2 Te < H_2Se < H_2 S < H_2O

  • Option 4)

    H_2Se < H_2 Te < H_2Po < H_2 O < H_2S

Answers (1)

 

Bond angle of hydrides of oxygen family -

All these hydrides are angular melocules and the bond angle H-X-H (X is O,S,Se,Te) 

decreases from H2O to H2Te

-

 

 

Thermal Stability of Hydride -

HF>HCl>HBr>HI

- wherein

Thermal stability increases with increase in electronegativity difference 

 

 

 

Correct order for thermal stability:

H_2Po < H_2 Te < H_2Se < H_2 S < H_2O

Thermal Stability of hydrides of group 16 elements decreases down the group.

It is because M-H bond dissociation energy decreases down the group with an increase in the size of a centred atom.


Option 1)

H_2S < H_2 O < H_2Se < H_2 Te < H_2Po

Option 2)

H_2O < H_2 S < H_2Se < H_2 Te < H_2Po

Option 3)

H_2Po < H_2 Te < H_2Se < H_2 S < H_2O

Option 4)

H_2Se < H_2 Te < H_2Po < H_2 O < H_2S

Exams
Articles
Questions