The unit of thermal conductivity is : 

  • Option 1)

    JmK^{-1}

  • Option 2)

    Jm^{-1}K^{-1}

  • Option 3)

    WmK^{-1}

  • Option 4)

    Wm^{-1}K^{-1}

Answers (1)
V Vakul

Q=frac{KA(	heta_{1}-	heta_{2})t}{l}

K = \frac{Ql }{A \theta *t }\\\\ unit \rightarrow W/mk \\\\ W m^{-1 }k^{-1}


Option 1)

JmK^{-1}

Option 2)

Jm^{-1}K^{-1}

Option 3)

WmK^{-1}

Option 4)

Wm^{-1}K^{-1}

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