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Help me solve this Which is the correct order of increasing energy of the listed orbitals in the atom of titanium?

Which is the correct order of increasing energy of the listed orbitals in the atom of titanium?

• Option 1)

$3s\:\: 4s \:\: 3p \:\: 3d$

• Option 2)

$4s \:\: 3s \:\: 3p \:\: 3d$

• Option 3)

$3s \:\: 3p \:\: 3d \:\: 4s$

• Option 4)

$3s \:\: 3p\:\: 4s \:\: 3d$

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As learnt

Electronic Configuration -

The 'd' block elements follow the general configuration $(n-1)d^{1-10}(ns^{1-2})$.

-

According to the Aufbau Principle, e-s occupy lower energy orbitals before going higher. Electrons are assigned to orbitals in order of increasing value of n+l.

For subshells with some value of (n+l), e-s are assigned first to the sub shell with lower x.

n+l value                             Therefore, the correct order will be 3s 3p 4s 3d

3s              3+0=3

3p              3+1=4

3d              3+2=5

4s               4+0=4

Option 1)

$3s\:\: 4s \:\: 3p \:\: 3d$

This option is incorrect

Option 2)

$4s \:\: 3s \:\: 3p \:\: 3d$

This option is incorrect

Option 3)

$3s \:\: 3p \:\: 3d \:\: 4s$

This option is incorrect

Option 4)

$3s \:\: 3p\:\: 4s \:\: 3d$

This option is correct

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