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Match the metal ions given in Column I with the spin magnetic moments of the ions given in Column II and assign the correct code :

  Column I   Column II
a. Co3+ i. \sqrt8 B.M.
b. Cr3+ ii. \sqrt{35} B.M.
c. Fe3+ iii. \sqrt{3} B.M.
d. Ni2+ iv.

\sqrt{24} B.M.

    v. \sqrt{15} B.M.

 

  • Option 1)
    a b c d
    iv i ii iii

     

  • Option 2)
    a b c d
    i ii iii iv
  • Option 3)
    a b c d
    iv v ii i
  • Option 4)
    a b c d
    iii v i ii
 

Answers (1)

best_answer

As we learnt that 

Magnetic Moments (spin only) -

\sqrt{n\left ( n+2 \right )} where n= number of unpaired electron.

- wherein

Number of unpaired e^{-} s and corresponding magnetic moments

1\rightarrow 1.7\\2\rightarrow 2.8\\3\rightarrow 3.9\\4\rightarrow 4.9\\5\rightarrow 5.9

 

 

Magnetic  moment (\mu) = \sqrt{n(n+2)} B.M.

a.  Co^{3+} \rightarrow n =4

\mu = \sqrt{4(4+2)} = \sqrt{24} B.M.

b. Cr^{3+} \rightarrow n =3

\mu = \sqrt{3(3+2)} = \sqrt{15} B.M.

c. Fe^{3+} \rightarrow n =5

\mu = \sqrt{5(5+2)} = \sqrt{35} B.M.

d. Ni^{2+} \rightarrow n =2

\mu = \sqrt{2(2+2)} = \sqrt{8} B.M.

 


Option 1)

a b c d
iv i ii iii

 

This is incorrect.

Option 2)

a b c d
i ii iii iv

This is incorrect.

Option 3)

a b c d
iv v ii i

This is correct.

Option 4)

a b c d
iii v i ii

This is incorrect.

Posted by

divya.saini

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