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Cobalt (III) chloride forms several octahedral complexes with ammonia. Which of the following will not give test of chloride ions with silver nitrate at 25^{\circ}C?

  • Option 1)

    CoCl_{3}\cdot 4NH_{3}

  • Option 2)

    CoCl_{3}\cdot 5NH_{3}

  • Option 3)

    CoCl_{3}\cdot 6NH_{3}

  • Option 4)

    CoCl_{3}\cdot 3NH_{3}

 

Answers (1)

best_answer

As learned in concept no

Coordination Sphere -

The central atom/ion and the ligands attached to metal are enclosed in square bracket and this collectively termed as coordination sphere

- wherein

eg:

K_{4}\left [ Fe\left ( CN \right )_{6} \right ]

 K^{+} \rightarrow Counter ion

\left [ Fe\left ( CN \right )_{6} \right ]^{4-} \rightarrow  Coordination sphere

 

 

 The co-ordination number of Cobalt (III) in octahedral complex is 6. In CoCl_{3}.3NH_{3}, all we have is 6 ligands, which implies all of them are in the co-ordination sphere and won't ionize.

\therefore There will be no precipation of Ages and no test will be positive


Option 1)

CoCl_{3}\cdot 4NH_{3}

This is incorrect option

Option 2)

CoCl_{3}\cdot 5NH_{3}

This is incorrect option

Option 3)

CoCl_{3}\cdot 6NH_{3}

This is incorrect option

Option 4)

CoCl_{3}\cdot 3NH_{3}

This is correct option

Posted by

Aadil

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