# The given circuit has two ideal diodes connected as shown in the figure below. The current flowing through the resistance R1 will be Option 1) 2.5 A Option 2) 10.0 A Option 3) 1.43 A Option 4) 3.13 A

P -N junction as diode -

It is a one way device. It offers a low resistance when forward biased and high resistance when reverse biased.

- wherein

R = 0, Forward

$\rightarrow \infty$ Reverse

In the given figure $D_{1}$ is in Reverse biased mode. hence no current win flow through it while $D_{2}$   is in forward biased mode hence will offer Zero resistance

$\therefore R_{eff} = 2\Omega +2\Omega = 4\Omega$

I = $\frac{10v}{4\Omega }=2.5 A$

Correct Option is $1>$

Option 1)

2.5 A

This option is incorrect.

Option 2)

10.0 A

This option is incorrect.

Option 3)

1.43 A

This option is incorrect.

Option 4)

3.13 A

This option is incorrect.

Diode D1 is reverse biased so, it will block the current and diode D2 is forward biased, so it will pass the current.  Hence, the equivalent circuit becomes as shown in the figure.

Current in the circuit: Current flowing through the resistance

V=IR

I= V/R = 10/2+2 = 2.5 AMPERE

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