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  • How to solve this problem- - Current Electricity - NEET-2

Two cities are 150km apart. Electric power is sent from one city to another city through copper wires. the fall of potential per km is 8 volt and the average resistance per km is 0.5\Omega. The power loss in the wires is:

  • Option 1)

    19.2W

  • Option 2)

    19.2kW

  • Option 3)

    19.2J

  • Option 4)

    12.2kW

 

Answers (1)

best_answer

 

Power dissipiated in external resistance -

P=(frac{E}{R+r})^{2}R

-

 

 Power loss=\frac{V^{2}}{R}

V= 8 \times 150\:V=1200\:Volt

R= 0.5 \Omega /km \times 150=75 \Omega

Power loss= \frac{V^{2}}{R}-\frac{(1200)^{2}}{75}W=19.2 kW


Option 1)

19.2W

This option is incorrect.

Option 2)

19.2kW

This option is correct.

Option 3)

19.2J

This option is incorrect.

Option 4)

12.2kW

This option is incorrect.

Posted by

prateek

View full answer

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