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A particle having a mass of 10^{-2}kg carries a charge of 5\times 10^{-8} C. The particle is given an initial horozontal velocity of 10^{-5} ms^{-1} in the presence of electric field \vec{E} and magnetic field \vec{B}. To keep the particle moving in a horizontal direction, it is necesary that

(1) \vec{B} should be prependicular to the  direction of velocity and \vec{E} should be along the direction of velocity.

(2) Both \vec{B} and \vec{E} should be along  the direction of velocity.

(3) Both \vec{B} and \vec{E} are mutually prependicular and prependicular to the direction of velocity.

(4) \vec{B} should be along the direction of velocity and \vec{E} should be prependicular to the direction of velocity.

Which one of the following pairs of statements is possible?

  • Option 1)

    (2) and (4)

  • Option 2)

    (1) and (3)

  • Option 3)

    (3) and (4)

  • Option 4)

    (2) and (3)

 

Answers (1)

best_answer

 

Lorentz Force -

underset{F}{ ightarrow}= q [underset{E}{ ightarrow}+(underset{V}{ ightarrow} imes underset{B}{ ightarrow})]

- wherein

Lorentz equation 

 

 

For particle to move along a horizontal direction either net force is zero or force is along direction of valocity. This can happen when 

either

Both  \vec{B} and \vec{E}  should be along direction of valocity and 

Both  \vec{B}  and \vec{E}  are mutually prependicular and prependicular to the direction of valocity.

such that E = VB


Option 1)

(2) and (4)

Incorrect option

Option 2)

(1) and (3)

Incorrect option

Option 3)

(3) and (4)

Incorrect option

Option 4)

(2) and (3)

Correct option

Posted by

prateek

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