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  • How to solve this problem- - Oscillations and Waves - NEET

A transverse wave is represented by y = A sin (\omegat - kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?

  • Option 1)

    \piA/2

  • Option 2)

    \piA

  • Option 3)

    2\piA

  • Option 4)

    A

 

Answers (1)

best_answer

As we discussed

Relation between phase velocity and wave speed -

V_{P}= -V: frac{dy}{dx}

- wherein

V_{P}= particle velocity

V = wave velocity

frac{dy}{dx}= slope of curve

 

 Y = A Sin (wt- Kx)

Particle velocity Vp = dy / dt = Aw cos (wt - kx)

\therefore Vp max = AW

wave velocity = W / K

\therefore AW = W / K

i.e A = 1/K value k = 2\piA


Option 1)

\piA/2

Incorrect

Option 2)

\piA

Incorrect

Option 3)

2\piA

Correct

Option 4)

A

Incorrect

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perimeter

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