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  • I have a doubt, kindly clarify. A body initially at rest and sliding along a frictionless track from a height h (as shown in the figure) just completes a vertical circle of diameter AB = D. The height h is equal to

A body initially at rest and sliding along a frictionless track from a height h (as shown in the figure) just completes a vertical circle of diameter AB = D. The height h is equal to

  • Option 1)

    \frac{7}{5}D

  • Option 2)

    D

  • Option 3)

    \frac{3}{2}D

  • Option 4)

    \frac{5}{4}D

 

Answers (1)

best_answer

As we have learned

If only conservative forces act on a system, total mechnical energy remains constant -

K+U=Eleft ( constant ight )

Delta K+Delta U=0

Delta K=-Delta U

-

 

 For particles to complete circle 

v=\sqrt{5gR}

also v=\sqrt{gh}\Rightarrow \sqrt{2gh}=\sqrt{5g-\frac{D}{2}}

h= \frac{5D}{4}

 

 

 

 


Option 1)

\frac{7}{5}D

This is incorrect

Option 2)

D

This is incorrect

Option 3)

\frac{3}{2}D

This is incorrect

Option 4)

\frac{5}{4}D

This is correct

Posted by

Plabita

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